X^2+7x-312=0

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Solution for X^2+7x-312=0 equation: 



X^2+7X-312=0

a = 1; b = 7; c = -312;
Δ = b2-4ac
Δ = 72-4·1·(-312)
Δ = 1297
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1297}}{2*1}=\frac{-7-\sqrt{1297}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1297}}{2*1}=\frac{-7+\sqrt{1297}}{2}
$

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